3.1. Short and simple proof of Fermat's theorem Theorem Proof |
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cN = bN + aN, | (3.1) |
in order to eliminate secondary solutions, we additionally assume that
N The following relation applies for odd numbers N: |
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, | (3.2) |
which means that cN must be divisible by a+b. By introducing two integer variables: s=a+b and x=s−c we obtain: |
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, | (3.3) |
which applies for each natural N > 0 and maintains the required
(per 3.2) The expression in square brackets in (3.3) could represent an integer number, This can be written as s=w‧ v and x=w‧ u, where v, u are natural numbers. By inserting these relations to (3.3) we can notice that left side of the equation (3.3) contains a multiplier wN, which should be also presented on the right side of the equation. |
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. | (3.4) |
We can see that an existence of required common divisor of
s and x
does not cause that expression in sqaure brackets in (3.3) is an integer number; if w
would be the greatest common divisor then
v and u
would be relatively prime, then (after taking wN-1 outside the brackets)
the expression in square brackets cannot be an integer number. |
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, | (3.5) |
where it is clearly visible that expression in square brackets cannot be an integer number. Thus, the natural, non-zero numbers s and x satisfying (3.3) do not exist. We have shown above that the theorem is true for N > 2, being a prime number and for all compound exponents N > 2 containing divisors which are prime numbers different than 2. In conjunction with the fact, that the theorem is true for N= 4
(End of proof) |